#coding=utf-8 # 解题思路： 关键点：变量逻辑状态的定义  20190302 找工作期间 class Solution(object): def removeDuplicates(self, nums): """ :type nums: List[int] :rtype: int """ if not nums: return None k = 0 value = nums[0] count = 1 for i in range(1,len(nums)): if count < 2: if nums[i] == value: count += 1 k += 1 nums[k] = nums[i] else: k += 1 nums[k] = nums[i] value = nums[k] count = 1 else: if nums[i] != value: k += 1 nums[k] = nums[i] value = nums[k] count = 1 return k+1 nums = [1,1,1,2,2,3] nums2 = [0,0,1,1,1,1,2,3,3] # [0,0,1,1,2,1,2] # [0,0,1,1,2,3,3] s = Solution() n1 =s.removeDuplicates(nums2) print n1 print nums2